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修复send_api中command_to_stream未使用display_name的问题

pull/1061/head
A0000Xz 2025-06-25 13:21:05 +08:00 committed by GitHub
parent 1ba1b85f7d
commit 8389bdb6d9
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1 changed files with 2 additions and 2 deletions
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4
src/plugin_system/apis/send_api.py
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@ -284,7 +284,7 @@ async def image_to_stream(image_base64: str, stream_id: str, storage_message: bo
return await _send_to_target("image", image_base64, stream_id, "", typing=False, storage_message=storage_message) return await _send_to_target("image", image_base64, stream_id, "", typing=False, storage_message=storage_message)
async def command_to_stream(command: Union[str, dict], stream_id: str, storage_message: bool = True) -> bool: async def command_to_stream(command: Union[str, dict], stream_id: str, storage_message: bool = True, display_message: str = "") -> bool:
"""向指定流发送命令 """向指定流发送命令
Args: Args:
@ -295,7 +295,7 @@ async def command_to_stream(command: Union[str, dict], stream_id: str, storage_m
Returns: Returns:
bool: 是否发送成功 bool: 是否发送成功
""" """
return await _send_to_target("command", command, stream_id, "", typing=False, storage_message=storage_message) return await _send_to_target("command", command, stream_id, display_message, typing=False, storage_message=storage_message)
async def custom_to_stream( async def custom_to_stream(