修复戳一戳,同时阻止自身的戳一戳回调
parent
cae9645fb7
commit
588ba6417e
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@ -165,68 +165,67 @@ class NoticeHandler:
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logger.info("发送到Maibot处理通知信息")
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await message_send_instance.message_send(message_base)
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async def handle_poke_notify(self, raw_message: dict, group_id: int, user_id: int) -> Tuple[Seg | None, UserInfo]:
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async def handle_poke_notify(self, raw_message: dict, group_id: int, user_id: int) -> Tuple[Seg | None, UserInfo | None]:
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self_info: dict = await get_self_info(self.server_connection)
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if not self_info:
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logger.error("自身信息获取失败")
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return None
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return None, None
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self_id = raw_message.get("self_id")
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target_id = raw_message.get("target_id")
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target_name: str = None
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raw_info: list = raw_message.get("raw_info")
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# 计算user_info
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source_name: str = None
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source_cardname: str = None
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if group_id:
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member_info: dict = await get_member_info(self.server_connection, group_id, user_id)
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if member_info:
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source_name = member_info.get("nickname")
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source_cardname = member_info.get("card")
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else:
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logger.warning("无法获取戳一戳消息发送者的昵称,消息可能会无效")
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source_name = "QQ用户"
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user_qq_info: dict = await get_member_info(
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self.server_connection, group_id, user_id
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)
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if user_qq_info:
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user_name = user_qq_info.get("nickname")
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user_cardname = user_qq_info.get("card")
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else:
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stranger_info = await get_stranger_info(self.server_connection, user_id)
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if stranger_info:
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source_name = stranger_info.get("nickname")
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else:
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logger.warning("无法获取戳一戳消息发送者的昵称,消息可能会无效")
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source_name = "QQ用户"
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user_info: UserInfo = UserInfo(
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platform=global_config.maibot_server.platform_name,
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user_id=user_id,
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user_nickname=source_name,
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user_cardname=source_cardname,
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)
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user_name = "QQ用户"
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user_cardname = "QQ用户"
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logger.info("无法获取戳一戳对方的用户昵称")
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# 计算Seg
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if self_id == target_id:
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if self_id == target_id: # 现在这里应当是专注于处理私聊戳一戳的,也就是说当私聊里,被戳的是另一方时,不会给这个消息。
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display_name = ""
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target_name = self_info.get("nickname")
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elif self_id == user_id:
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return None, None # 这应当让ada不发送麦麦戳别人的消息,因为这个消息已经被mmc的命令记录了,没必要记第二次。
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else:
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return None
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if group_id: # 如果是群聊环境,老实说做这一步判定没啥意义,毕竟私聊是没有其他人之间的戳一戳的,但是感觉可以有这个判定来强限制群聊环境
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fetched_member_info: dict = await get_member_info(
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self.server_connection, group_id, target_id
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)
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if fetched_member_info:
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target_name = fetched_member_info.get("nickname")
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else:
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target_name = "QQ用户"
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logger.info("无法获取被戳一戳方的用户昵称")
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display_name = user_name
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else:
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return None, None
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try:
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first_txt = raw_info[2].get("txt", "戳了戳")
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second_txt = raw_info[4].get("txt", "")
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except Exception as e:
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logger.warning(f"解析戳一戳消息失败: {str(e)},将使用默认文本")
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first_txt = "戳了戳"
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second_txt = ""
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"""
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# 不启用戳其他人的处理
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else:
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# 由于Napcat不支持获取昵称,所以需要单独获取
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group_id = raw_message.get("group_id")
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fetched_member_info: dict = await get_member_info(
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self.server_connection, group_id, target_id
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)
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if fetched_member_info:
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target_name = fetched_member_info.get("nickname")
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"""
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user_info: UserInfo = UserInfo(
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platform=global_config.maibot_server.platform_name,
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user_id=user_id,
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user_nickname=user_name,
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user_cardname=user_cardname,
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)
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seg_data: Seg = Seg(
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type="text",
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data=f"{first_txt}{target_name}{second_txt}(这是QQ的一个功能,用于提及某人,但没那么明显)",
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data=f"{display_name}{first_txt}{target_name}{second_txt}(这是QQ的一个功能,用于提及某人,但没那么明显)",
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)
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return seg_data, user_info
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